From a527f65a9aab6003e6f48a9a33192f7a62fbc053 Mon Sep 17 00:00:00 2001
From: serr <sc7227484@gmail.com>
Date: Thu, 9 Jan 2025 02:00:19 +0300
Subject: [PATCH] =?UTF-8?q?=D0=BF=D1=80=D0=B8=D1=87=D0=B5=D1=81=D0=B0?=
 =?UTF-8?q?=D0=BB=20=D1=87=D1=83=D1=82=D0=BA=D0=B0=20=D0=BA=D0=BE=D0=B4?=
MIME-Version: 1.0
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Content-Transfer-Encoding: 8bit

---
 chain_fraction.py | 24 ++++++++++--------------
 euclid.py         |  3 +--
 2 files changed, 11 insertions(+), 16 deletions(-)

diff --git a/chain_fraction.py b/chain_fraction.py
index 5beb5af..9a78959 100644
--- a/chain_fraction.py
+++ b/chain_fraction.py
@@ -23,28 +23,24 @@ def get_p_n(n, q_list):
 def get_x0(a, b, m):
     q_list = get_q_list(m, a)
     n = len(q_list) - 1
-    p = get_p_n(n-1, q_list)
-    x = ((-1)**n*p*b)%m
-    return x, f'x={x}mod{m}'
+    p = get_p_n(n-1, get_q_list(m, a))
+    x0 = ((-1)**n*p*b)%m
+    return x0
 
 def solve(task):
     f = re.fullmatch(r'(\d+)x=(\d+)mod(\d+)', task)
     if f == None:
         return "Usage Example: py chain_fraction.py '7x=8mod13'"
     a, b, m = int(f.groups()[0]), int(f.groups()[1]), int(f.groups()[2]) 
-    d = gcd(a, m) # Находим НОД
-    if d == 1: # нод = 1 => 1 решение
-        return get_x0(a, b, m)[1]
+    d = gcd(a, m)
     if d > 1 and b % d != 0:
         return 'No solutions'
-    else:
-        d = gcd(gcd(a, b), m)
-        a1, b1, m1 = a // d, b // d, m // d
-        x0 = get_x0(a1, b1, m1)[0]
-        s = ""
-        for k in range(d):
-            s += f'x={(x0+m1*k)%m}mod{m}\n'
-        return s[:-1]
+    a1, b1, m1 = a // d, b // d, m // d
+    x0 = get_x0(a1, b1, m1)
+    s = ""
+    for i in range(d):
+        s += f'x={(x0+m//d*i)%m}mod{m}\n'
+    return s[:-1]
 
 if __name__ == "__main__":
     if len(sys.argv) != 2:
diff --git a/euclid.py b/euclid.py
index a4fb877..e1933fe 100644
--- a/euclid.py
+++ b/euclid.py
@@ -17,8 +17,7 @@ def solve(task):
     if d > 1 and b % d != 0:
         return 'No solutions'
     a1, b1, m1 = a // d, b // d, m // d
-    u, _, _ = gcd(a1, m1)
-    x0 = b1*u
+    x0 = b1*gcd(a1, m1)[0]
     s = ""
     for i in range(0, d):
         s += f'x={(x0+m//d*i)%m}mod{m}\n'